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ValidAnagram.java
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106 lines (77 loc) · 2.52 KB
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package Algorithms.Hashing;
import java.util.Arrays;
import java.util.function.Function;
import java.util.stream.Collectors;
/**
* @author Srinivas Vadige, srinivas.vadige@gmail.com
* @since 06 Sept 2025
* @link 242. Valid Anagram <a href="https://leetcode.com/problems/valid-anagram/">Leetcode link</a>
* @topics Hash Table, String, Sorting
*/
public class ValidAnagram {
public static void main(String[] args) {
String s = "anagram";
String t = "nagaram";
System.out.println(isAnagram(s, t));
}
/**
* @TimeComplexity O(n)
* @SpaceComplexity O(1)
*/
public static boolean isAnagram(String s, String t) {
if(s.length() != t.length()) return false;
int[] freq = new int[26];
for(int i=0; i<s.length(); i++) {
freq[s.charAt(i)-'a']++;
freq[t.charAt(i)-'a']--;
}
// for(int f: freq) {
// if(f != 0) return false;
// }
// return true;
return Arrays.stream(freq).allMatch(i->i==0);
}
public static boolean isAnagram2(String s, String t) {
if(s.length()!=t.length()) {
return false;
}
int[] freq = new int[26];
for(int i = 0 ;i<s.length();i++) {
freq[s.charAt(i)-'a']++;
}
for(int i = 0 ;i<t.length();i++){
if(--freq[t.charAt(i)-'a']<0){
return false;
}
}
return true;
}
/**
* @TimeComplexity O(n) + O(nlogn) = O(nlogn)
* @SpaceComplexity O(n)
*/
public static boolean isAnagram3(String s, String t) {
if (s.length() != t.length()) {
return false;
}
char[] sArr = s.toCharArray();
char[] tArr = t.toCharArray();
Arrays.sort(sArr);
Arrays.sort(tArr);
return Arrays.equals(sArr, tArr); // arrays are objects, but they inherit the default equals() but dont override equals() ---> always compare arrays using Arrays.equals()
/*
// or
String sStr = Arrays.toString(sArr);
String tStr = Arrays.toString(tArr);
return sStr.equals(tStr);
*/
}
/**
* @TimeComplexity O(n)
* @SpaceComplexity O(n)
*/
public static boolean isAnagram4(String s, String t) {
return Arrays.stream(s.split("")).collect(Collectors.groupingBy(Function.identity(), Collectors.counting()))
.equals(Arrays.stream(t.split("")).collect(Collectors.groupingBy(Function.identity(), Collectors.counting())));
}
}