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rle.py
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127 lines (98 loc) · 2.64 KB
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"""
*
* 游程编码 (RLE) - 简单的压缩算法
*
* 问题:将连续重复的字符压缩为字符+计数的形式
*
* 核心思想:
* - 统计连续相同字符的数量
* - 用字符+计数表示重复序列
*
* 时间复杂度: O(n)
* 空间复杂度: O(n)
"""
def compress(text: str) -> str:
"""
压缩函数
Args:
text: 输入文本
Returns:
压缩后的文本
"""
if not text:
return text
compressed = []
current_char = text[0]
count = 1
for i in range(1, len(text)):
if text[i] == current_char:
count += 1
else:
compressed.append(current_char)
if count > 1:
compressed.append(str(count))
current_char = text[i]
count = 1
# 处理最后一个字符
compressed.append(current_char)
if count > 1:
compressed.append(str(count))
return ''.join(compressed)
def decompress(compressed: str) -> str:
"""
解压函数
Args:
compressed: 压缩后的文本
Returns:
解压后的文本
"""
if not compressed:
return compressed
decompressed = []
i = 0
while i < len(compressed):
current_char = compressed[i]
i += 1
count_str = ""
# 解析数字
while i < len(compressed) and compressed[i].isdigit():
count_str += compressed[i]
i += 1
count = 1
if count_str:
count = int(count_str)
# 添加字符
decompressed.append(current_char * count)
return ''.join(decompressed)
def compression_ratio(original: str, compressed: str) -> float:
"""
计算压缩比
Args:
original: 原始文本
compressed: 压缩后的文本
Returns:
压缩比
"""
return len(compressed) / len(original)
def main():
"""主函数"""
text = "AAAABBBCCDAA"
print("=== 游程编码 (RLE) ===")
print(f"原始文本: {text}")
compressed = compress(text)
print(f"压缩后: {compressed}")
decompressed = decompress(compressed)
print(f"解压后: {decompressed}")
print(f"压缩比: {compression_ratio(text, compressed):.2f}")
print(f"验证: {text == decompressed}")
# 测试用例2
print("\n测试用例2:")
text2 = "WWWWWWWWWWWWBWWWWWWWWWWWWBBBWWWWWWWWWWWWWWWWWWWWWWWWB"
compressed2 = compress(text2)
decompressed2 = decompress(compressed2)
print(f"原始文本: {text2}")
print(f"压缩后: {compressed2}")
print(f"解压后: {decompressed2}")
print(f"验证: {text2 == decompressed2}")
if __name__ == "__main__":
main()